Sử dụng hàm IF() kết hợp với IS NULL. Tạo bảng mẫu:
mysql> create table DemoTable1976 ( FirstName varchar(20), LastName varchar(20) ); Query OK, 0 rows affected (0.00 sec)
Thêm bản ghi:
mysql> insert into DemoTable1976 values('John','Doe'); Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1976 values('John',NULL); Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1976 values(NULL,'Miller'); Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1976 values('Chris','Brown'); Query OK, 1 row affected (0.00 sec)
Hiển thị dữ liệu ban đầu:
mysql> select * from DemoTable1976;
+-----------+----------+ | FirstName | LastName | +-----------+----------+ | John | Doe | | John | NULL | | NULL | Miller | | Chris | Brown | +-----------+----------+ 4 rows in set (0.00 sec)
Truy vấn cập nhật: nếu FirstName NULL thì gán 'David', nếu LastName NULL thì gán 'Brown', cả hai không NULL thì giữ nguyên:
mysql> update DemoTable1976 set FirstName=if(FirstName IS NULL,'David',FirstName), LastName=if(LastName IS NULL,'Brown',LastName); Query OK, 2 rows affected (0.00 sec) Rows matched: 4 Changed: 2 Warnings: 0
Kiểm tra lại:
mysql> select * from DemoTable1976;
+-----------+----------+ | FirstName | LastName | +-----------+----------+ | John | Doe | | John | Brown | | David | Miller | | Chris | Brown | +-----------+----------+ 4 rows in set (0.00 sec)