Cú pháp kết hợp IN và IS NULL:
SELECT cot1, cot2, cot3 FROM tenBang
WHERE giaTri IN (cot1, cot2) OR cot1 IS NULL;
Tạo bảng demo60:
mysql> CREATE TABLE demo60 (
-> id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
-> first_name VARCHAR(20),
-> last_name VARCHAR(20)
-> );
Chèn dữ liệu (có giá trị NULL):
mysql> INSERT INTO demo60(first_name,last_name) VALUES('John','Smith');
mysql> INSERT INTO demo60(first_name,last_name) VALUES('John','Doe');
mysql> INSERT INTO demo60(first_name,last_name) VALUES(NULL,'Brown');
mysql> INSERT INTO demo60(first_name,last_name) VALUES('David','Miller');
mysql> INSERT INTO demo60(first_name,last_name) VALUES('David','Smith');
mysql> INSERT INTO demo60(first_name,last_name) VALUES('Chris','Brown');
Hiển thị dữ liệu:
mysql> SELECT * FROM demo60;
+----+------------+-----------+
| id | first_name | last_name |
+----+------------+-----------+
| 1 | John | Smith |
| 2 | John | Doe |
| 3 | NULL | Brown |
| 4 | David | Miller |
| 5 | David | Smith |
| 6 | Chris | Brown |
+----+------------+-----------+
Truy vấn: lấy hàng có 'John' trong first_name hoặc last_name, HOẶC first_name IS NULL:
mysql> SELECT id, first_name, last_name
-> FROM demo60
-> WHERE 'John' IN (first_name, last_name) OR first_name IS NULL;
Kết quả:
+----+------------+-----------+
| id | first_name | last_name |
+----+------------+-----------+
| 1 | John | Smith |
| 2 | John | Doe |
| 3 | NULL | Brown |
+----+------------+-----------+