Cú pháp sử dụng SUM trên biểu thức boolean:
SELECT SUM(cot1 + cot2 + cot3) AS TongSoGiaTri1,
SUM(cot1 AND cot2 AND cot3) AS SoHangCoTatCa1
FROM tenBang;
Tạo bảng demo36:
mysql> CREATE TABLE demo36 (
-> id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
-> value1 INT,
-> value2 INT,
-> value3 INT
-> );
Chèn dữ liệu:
mysql> INSERT INTO demo36(value1,value2,value3) VALUES(1,0,0);
mysql> INSERT INTO demo36(value1,value2,value3) VALUES(1,0,1);
mysql> INSERT INTO demo36(value1,value2,value3) VALUES(1,1,1);
mysql> INSERT INTO demo36(value1,value2,value3) VALUES(0,1,0);
mysql> INSERT INTO demo36(value1,value2,value3) VALUES(1,1,0);
Hiển thị dữ liệu:
mysql> SELECT * FROM demo36;
Kết quả:
+----+--------+--------+--------+
| id | value1 | value2 | value3 |
+----+--------+--------+--------+
| 1 | 1 | 0 | 0 |
| 2 | 1 | 0 | 1 |
| 3 | 1 | 1 | 1 |
| 4 | 0 | 1 | 0 |
| 5 | 1 | 1 | 0 |
+----+--------+--------+--------+
Truy vấn đếm:
mysql> SELECT
-> SUM(value1+value2+value3) AS `Total_Number_Of_1`,
-> SUM(value1 AND value2 AND value3) AS `Total_Number_Of_Rows_With_1`
-> FROM demo36;
Kết quả:
+-------------------+-----------------------------+
| Total_Number_Of_1 | Total_Number_Of_Rows_With_1 |
+-------------------+-----------------------------+
| 9 | 1 |
+-------------------+-----------------------------+