Đôi khi cần xác định dữ liệu không khớp giữa hai bảng, đặc biệt khi migrate dữ liệu. So sánh bằng cách dùng UNION ALL + GROUP BY + HAVING COUNT(*) = 1. Ví dụ hai bảng students và student1:
mysql> Select * from students; +--------+--------+----------+ | RollNo | Name | Subject | +--------+--------+----------+ | 100 | Gaurav | Computer | | 101 | Raman | History | | 102 | Somil | Computer | +--------+--------+----------+ 3 rows in set (0.00 sec) mysql> select * from student1; +--------+--------+----------+ | RollNo | Name | Subject | +--------+--------+----------+ | 100 | Gaurav | Computer | | 101 | Raman | History | | 102 | Somil | Computer | | 103 | Rahul | DBMS | | 104 | Aarav | History | +--------+--------+----------+ 5 rows in set (0.00 sec)
Truy vấn tìm hàng không khớp:
mysql> Select RollNo,Name,Subject from (select RollNo,Name,Subject from students union all select RollNo,Name,Subject from Student1) as std GROUP BY RollNo,Name,Subject HAVING Count(*) = 1 ORDER BY RollNo; +--------+-------+---------+ | RollNo | Name | Subject | +--------+-------+---------+ | 103 | Rahul | DBMS | | 104 | Aarav | History | +--------+-------+---------+ 1 rows in set (0.02 sec)