Dùng toán tử $where với find() để so sánh hai trường. Cú pháp:
db.yourCollectionName.find({$where:"yourCondition"}).pretty();
Tạo collection compareTwoFields:
>db.compareTwoFields.insert({"Id":1,"FullName":{"FirstName":"John","LastName":"Smith"}, "BranchName":"ComputerScience"});
WriteResult({ "nInserted" : 1 })
>db.compareTwoFields.insert({"Id":2,"FullName":{"FirstName":"Smith","LastName":"Smith"}, "BranchName":"Civil"});
WriteResult({ "nInserted" : 1 })
>db.compareTwoFields.insert({"Id":3,"FullName":{"FirstName":"David","LastName":"Smith"}, "BranchName":"Mechanical"});
WriteResult({ "nInserted" : 1 })
Hiển thị:
> db.compareTwoFields.find().pretty();
So sánh FirstName và LastName bằng nhau:
>db.compareTwoFields.find({$where:"this.FullName.FirstName==this.FullName.LastName"}).pretty();
Kết quả (chỉ Id=2 khớp):
{ "_id" : ObjectId("5c6c239868174aae23f5ef65"), "Id" : 2, "FullName" : { "FirstName" : "Smith", "LastName" : "Smith" }, "BranchName" : "Civil" }